How do you find the derivative of #y=xe^x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Andrea S. May 8, 2017 Using the product rule: #dy/dx = d/dx (xe^x) = x xx d/dx (e^x) + d/dx(x) xx e^x = xe^x+e^x = e^x(x+1)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 7778 views around the world You can reuse this answer Creative Commons License