# How do you find the derivative of y=xe^x?

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{d}{\mathrm{dx}} \left(x {e}^{x}\right) = x \times \frac{d}{\mathrm{dx}} \left({e}^{x}\right) + \frac{d}{\mathrm{dx}} \left(x\right) \times {e}^{x} = x {e}^{x} + {e}^{x} = {e}^{x} \left(x + 1\right)$