# How do you find the determinant of #((-9, -7), (4, 5))#?

##### 1 Answer

Feb 9, 2016

The determinant is

#### Explanation:

For a

#A = ( (a, b), (c, d)) # ,

the determinant can be computed as

#|A| = a * d - b * c#

Thus, in your example,

#abs( ( (-9, -7), (4, 5) ) ) = -9 * 5 - (-7)* 4 = -45 + 28 = -17#