# How do you find the diagonal of a rectangle whose length is 125 feet and whose width is 80 feet?

Oct 15, 2015

You may see the two sides and the diagonal as a rectangular triangle, so Pythagoras can be used.

#### Explanation:

Diagonal=hypotenuse.

${d}^{2} = {a}^{2} + {b}^{2} = {125}^{2} + {80}^{2}$

So the diagonal is:

$d = \sqrt{{125}^{2} + {80}^{2}}$