# How do you find the discriminant for 0.2x^2-1.5x+2.9=0 and determine the number and type of solutions?

May 15, 2017

see explanation

#### Explanation:

$0.2 {x}^{2} - 1.5 x + 2.9 = 0$

To find the discriminant of an equation,
first, you must make the equation into the form of
$a {x}^{2} + b x + c = 0$
And the discriminant will be ${b}^{2} - 4 a c$

if the discriminant =0,then the equation has two equal real roots
if the discriminant >0,the the equation will have two different real roots
if the discriminant < 0, the the equation will have no real roots.

so based on the given equation
we can write out that
discriminant=${\left(- 1.5\right)}^{2} - 4 \left(0.2\right) \left(2.9\right)$
=-0.07
because the discriminant of the equation is < 0
so we can tell that the equation has no real roots.