How do you find the discriminant for #0.2x^2-1.5x+2.9=0# and determine the number and type of solutions?

1 Answer
May 15, 2017

Answer:

see explanation

Explanation:

#0.2x^2-1.5x+2.9=0#

To find the discriminant of an equation,
first, you must make the equation into the form of
#ax^2+bx+c=0#
And the discriminant will be #b^2-4ac#

if the discriminant =0,then the equation has two equal real roots
if the discriminant >0,the the equation will have two different real roots
if the discriminant < 0, the the equation will have no real roots.

so based on the given equation
we can write out that
discriminant=#(-1.5)^2-4(0.2)(2.9)#
=-0.07
because the discriminant of the equation is < 0
so we can tell that the equation has no real roots.