How do you find the discriminant x^2+x-12x2+x12?

1 Answer
May 3, 2016

49

Explanation:

Given a quadratic equation in standard form ax^2 +bx+c=0 ax2+bx+c=0

Then the discriminant color(red)(|bar(ul(color(white)(a/a)color(black)((Delta)=b^2-4ac)color(white)(a/a)|)))

The value of the discriminant gives information on the color(blue)" nature of the roots "

• b^2-4ac > 0 " roots are real and irrational "

However if b^2-4ac " is a square , roots are real and rational"

• b^2-4ac=0 " roots are real and equal "

• b^2-4ac < " roots are not real "

For the given function here x^2+x-12 , a=1,b=1,c=-12

rArr b^2-4ac=1^2-(4xx1xx-12)=49

Since b^2-4ac > 0 " and a square , roots will be real and rational"