How do you find the discriminant x^2+x-12x2+x−12?
1 Answer
May 3, 2016
49
Explanation:
Given a quadratic equation in standard form
ax^2 +bx+c=0 ax2+bx+c=0 Then the discriminant
color(red)(|bar(ul(color(white)(a/a)color(black)((Delta)=b^2-4ac)color(white)(a/a)|))) The value of the discriminant gives information on the
color(blue)" nature of the roots "
• b^2-4ac > 0 " roots are real and irrational " However if
b^2-4ac " is a square , roots are real and rational"
• b^2-4ac=0 " roots are real and equal "
• b^2-4ac < " roots are not real " For the given function here
x^2+x-12 , a=1,b=1,c=-12
rArr b^2-4ac=1^2-(4xx1xx-12)=49 Since
b^2-4ac > 0 " and a square , roots will be real and rational"