How do you find the distance between (-2,6) and (-10,-9)?

Mar 30, 2017

$d = 17$

Explanation:

Find the $x$ value and the $y$ value of the distances and then use the squares of the $x$ and $y$ to find the square root of the sum of the $x$ and $y$ squares.

The x distance equals $- 2 - \left(- 10\right) = + 8$

The y distance equal $6 - \left(- 9\right) = + 15$

${x}^{2} + {y}^{2} = {d}^{2}$

${\left(8\right)}^{2} + {\left(15\right)}^{2} = {d}^{2}$

$64 + 225 = {d}^{2}$

$289 = {d}^{2}$

$\sqrt{289} = {\sqrt{d}}^{2}$

$d = 17$