# How do you find the distance between (3,3), (-2,3)?

Aug 30, 2016

5

#### Explanation:

let $P t A = \left(3 , 3\right) , P t B = \left(- 2 , 3\right)$
Line AB is horizontal, as the y-coordinates are the same
the distance between Pt A and Pt B is $3 - \left(- 2\right) = 5$