# How do you find the distance between (-4,1) and (3,-1)?

Nov 6, 2016

7.2801....

#### Explanation:

This is basically Pythagoras' therom just on a graph. As the shortest distance between these points will be straight and you can make a right-angled triangle from these co-ordinates

So you fin the difference in the x co-ordinates (3--4=7) and the difference in the y co-ordinates (1--1=2)

These are a and b in the equation ${a}^{2} + {b}^{2} = {c}^{2}$

So ${7}^{2} + {2}^{2} = 53$
distance between (-4,1) and (3,-1) = $\sqrt{53} = 7.2801 \ldots$