# How do you find the distance between (-6,3), (10,3)?

Jul 19, 2016

Distance: $\textcolor{g r e e n}{16 \text{ units}}$
$\left(- 6 , 3\right)$ and $\left(10 , 3\right)$ are two points on the horizontal line $y = 3$
$\left(- 6 , 3\right)$ is $6$ units to the left of the Y-axis;
$\left(10 , 3\right)$ is $10$ units to the right of the Y-axis;
giving a total distance of $6 + 10 = 16 \text{ units}$ between the points.