# How do you find the distance between (6,-7), (3,-5)?

Feb 14, 2017

#### Answer:

sqrt13≈3.606" to 3 dec.places"

#### Explanation:

To calculate the distance use the $\textcolor{b l u e}{\text{distance formula}}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where $\left({x}_{1} , {y}_{1}\right) , \left({x}_{2} , {y}_{2}\right) \text{ are 2 coordinate points}$

The 2 points here are (6 ,-7) and (3 ,-5)

let $\left({x}_{1} , {y}_{1}\right) = \left(6 , - 7\right) \text{ and } \left({x}_{2} , {y}_{2}\right) = \left(3 , - 5\right)$

$d = \sqrt{{\left(3 - 6\right)}^{2} + {\left(- 5 + 7\right)}^{2}}$

$\textcolor{w h i t e}{d} = \sqrt{9 + 4}$

color(white)(d)=sqrt13≈3.606" to 3 decimal places"