# How do you find the distance between point A(-3, 5) and point B(4, -6) in the coordinate plane?

The distance AB can be calculated by applying the theorem of Pythagoras in the triangle ABC, where C is the point of coordinates $\left(- 3 , - 6\right)$.
$A {B}^{2} = A {C}^{2} + B {C}^{2}$
$A C = 5 + 6 = 11$ and $B C = 3 + 4 = 7$
Therefore, $A {B}^{2} = {11}^{2} + {7}^{2} = 121 + 49 = 170$ $\implies$ $A B = \sqrt{170}$