How do you find the distance between (sqrt2,-7sqrt3), (4sqrt2,8sqrt3)?

Distance is $3 \sqrt{77}$ unit.
Distance formula : $d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}} = \sqrt{{\left(4 \sqrt{2} - \sqrt{2}\right)}^{2} + {\left(8 \sqrt{3} + 7 \sqrt{3}\right)}^{2}} = \sqrt{{\left(3 \sqrt{2}\right)}^{2} + {\left(15 \sqrt{3}\right)}^{2}} = \sqrt{18 + 675} = \sqrt{693} = \sqrt{9 \cdot 77} = 3 \sqrt{77}$ unit [Ans]