How do you find the domain and range for #(x-6)^2+(y-5)^2=4#?

1 Answer
Nov 12, 2016

Answer:

Domain: #4<=x<=8#

Range: #3<=y<=7#

Explanation:

The equation you've given is the equation of a circle. In other words, it is not a function, but a relation. However, relations still have domains and ranges. The easiest way to find the range and domain of your equation would be to graph it:

graph{(x-6)^2 + (y-5)^2 = 4 [-4.295, 15.705, 0.32, 10.32]}