# How do you find the domain and range of  (2/3)^x – 9?

Domain: $\left(- \infty , + \infty\right)$
Range: $\left(- 9 , + \infty\right)$

#### Explanation:

For the domain:
x can take any value. Therefore
Domain: $\left(- \infty , + \infty\right)$

The horizontal asymptote of the graph is $y = - 9$, therefore it does not include the value $y = 9$. It is the approached value of the function as x approaches $+ \infty$

Range: $\left(- 9 , + \infty\right)$

Kindly see the graph for visual aid.

God bless....I hope the explanation is useful.