How do you find the domain for #f(x) = 1/(sqrt(3-2x))#?
Whenever you are dealing with domain/range of a function that involves a radical, you need to set the radical to the following:
Interestingly, this is also a rational function. Therefore, we must determine any vertical asymptotes. Vertical asymptotes in a rational function can be found by setting the denominator to 0 and solving for x. Doing this:
In the domain statement, we can say that
Hopefully this makes sense!