How do you find the domain of 1/(sqrt(17-t))?

Mar 28, 2018

$\left\{t \in \mathbb{R} | - \infty < t < 17\right\}$

Explanation:

$\frac{1}{\sqrt{17 - t}}$

For real numbers the radicand ( value inside the radical ) must be greater than zero. We can't allow zero, because this would be undefined, ( division by zero ).

$\therefore$

$17 - t > 0$

$t < 17$

So domain is:

$\left(- \infty , 17\right)$

or in set notation:

$\left\{t \in \mathbb{R} | - \infty < t < 17\right\}$