How do you find the domain of #f(x)=(log[x-4])/(log[3])#?

1 Answer
May 21, 2015

The domain of function #f(x)# is the interval #(4;+infty)#.

First you need to know that you can evaluate #log(x)# only when #x# is positive (#x>0#) and equals #0# only when #x=1#.

So, in our denominator we don't any problems, #3# is a positive number different that #1# so we get a nonzero denominator.

Our numerator consists of #log(x-4)#, which can be #0# but this doesn't concern us particularly. The number inside, #x-4#, must be positive, though. So:

# x-4>0 #
# x>4 #
#x in (4;+infty)#