# How do you find the domain of y =-sqrt(x+1 )-6?

##### 1 Answer
Mar 28, 2017

Assuming that y is restricted to a real number, ($y \in \mathbb{R}$), then the argument for the square root must be greater than or equal to 0:

#### Explanation:

$x + 1 \ge 0$

$x \ge - 1 \leftarrow$ This is the domain