How do you find the equation for a circle with center is (-2,-3) and radius 3?

1 Answer
Dec 2, 2015

Answer:

The equation for a circle with centre #(h, k)# and radius #r# can be written in standard form as:

#(x-h)^2+(y-k)^2 = r^2#

In our case:

#(x+2)^2+(y+3)^2 = 9#

Explanation:

A standard form for the equation of a circle of radius #r# and centre #(h, k)# is:

#(x-h)^2+(y-k)^2 = r^2#

In our case #h=-2#, #k=-3# and #r=3#, so:

#(x-(-2))^2 + (y-(-3))^2 = 3^2#

or more simply:

#(x+2)^2+(y+3)^2=9#