# How do you find the equation for a circle with center is (-2,-3) and radius 3?

##### 1 Answer

Dec 2, 2015

The equation for a circle with centre

#(x-h)^2+(y-k)^2 = r^2#

In our case:

#(x+2)^2+(y+3)^2 = 9#

#### Explanation:

A standard form for the equation of a circle of radius

#(x-h)^2+(y-k)^2 = r^2#

In our case

#(x-(-2))^2 + (y-(-3))^2 = 3^2#

or more simply:

#(x+2)^2+(y+3)^2=9#