# How do you find the equation of the circle passing through the point (2,6), with center (3,-5)?

equired equation would be ${\left(x - 3\right)}^{2} + {\left(y + 5\right)}^{2} = 122$
Here , it is needed to find the radius of the circle. It would be $\sqrt{{\left(2 - 3\right)}^{2} + {\left(6 + 5\right)}^{2}} = \sqrt{122}$
Required equation would be ${\left(x - 3\right)}^{2} + {\left(y + 5\right)}^{2} = 122$