How do you find the equation of the line parallel to 3x + 5y = 11 and has a y-intercept of -6?

2 Answers
Oct 9, 2017

Answer:

See the answer below...

Explanation:

The slope of the the straight line equation #3x+5y=11# is #(-3/5)#
Hence the slope of the line parallel is same to the given line i.e,#(-3/5)#
We can write the equation in the following form slope intercept form i.e, #y=mx+c#
Here #c=-6# and #m=-3/5#

The answer is #y=-3/5x-6=>5y=-3x-30=>3x+5y=-30#

Hope it helps...
Thanks you...

Oct 9, 2017

Answer:

The equation of the line is #y= 3x+5y = -30#

Explanation:

Parallel lines have equal slope. The slope of the line

#3x+5y=11 or y = -3/5x +11/5 [y=mx+c]# is #m=-3/5#

The required line has #y# intercept of #-6 or (0,-6) #

Let the required equation of the line is #y=mx+c # or

#y=-3/5x - 6 # since #m=-3/5 and c= -6 :.# The equation

of the line is #y=-3/5x - 6 or 3x+5y = -30#

graph{-3/5x-6 [-22.5, 22.5, -11.25, 11.25]} [Ans]