Question

How do you find the equation of the line parallel to 3x + 5y = 11 and has a y-intercept of -6?

Answer 1

See the answer below...

Explanation:

The slope of the the straight line equation `3x+5y=11` is `(-3/5)`
Hence the slope of the line parallel is same to the given line i.e,`(-3/5)`
We can write the equation in the following form slope intercept form i.e, `y=mx+c`
Here `c=-6` and `m=-3/5`

The answer is `y=-3/5x-6=>5y=-3x-30=>3x+5y=-30`

Hope it helps...
Thanks you...

Answer 2

The equation of the line is `y= 3x+5y = -30`

Explanation:

Parallel lines have equal slope. The slope of the line

`3x+5y=11 or y = -3/5x +11/5 [y=mx+c]` is `m=-3/5`

The required line has `y` intercept of `-6 or (0,-6)`

Let the required equation of the line is `y=mx+c` or

`y=-3/5x - 6` since `m=-3/5 and c= -6 :.` The equation

of the line is `y=-3/5x - 6 or 3x+5y = -30`

graph{-3/5x-6 [-22.5, 22.5, -11.25, 11.25]} [Ans]