# How do you find the equation of the line which has a y-intercept of 13 and is parallel to the line joining the points (8, 12) and (-9, 10)?

##### 1 Answer

Jun 28, 2016

#### Answer:

#### Explanation:

A line with a y-intercept of 13 passes through the point

A line parallel to the line joining the points

has the same slope as the line joining

Using the point-slope form:

graph{(2x-17y+221)((x-8)^2+(y-12)^2-0.1)((x+9)^2+(y-10)^2-0.1)=0 [-14.63, 17.4, 5.02, 21.04]}