How do you find the equation of the line with slope m=7/8 and point (1,-2)?
1 Answer
Jan 3, 2017
Explanation:
The equation of a line in
#color(blue)"point-slope form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line".#
#"here " m=7/8" and " (x_1,y_1)=(1,-2)# substitute these values into the equation.
#y+2=7/8(x-1)larr" in point-slope form"# If we distribute and simplify we obtain an alternative form of the equation.
#y+2=7/8x-7/8#
#rArry=7/8x-7/8-2#
#rArry=7/8x-23/8larr" in slope-intercept form"#