How do you find the equation of the line with slope m=7/8 and point (1,-2)?

1 Answer
Jan 3, 2017

#y=7/8x-23/8#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line".#

#"here " m=7/8" and " (x_1,y_1)=(1,-2)#

substitute these values into the equation.

#y+2=7/8(x-1)larr" in point-slope form"#

If we distribute and simplify we obtain an alternative form of the equation.

#y+2=7/8x-7/8#

#rArry=7/8x-7/8-2#

#rArry=7/8x-23/8larr" in slope-intercept form"#