How do you find the equation of the tangent to the curve #y = 2 - sin^2 x# at the point where x = pi/6?
One important thing to note when finding the equation of a tangent to a curve at a given point is that the slope of the tangent is equal to the value of first derivative at that point.
As the function is
For slope, as
and slope at
Using point slope form of equation
equation of tangent is