# How do you find the exact solutions to the system #2x^2+8y^2+8x-48y+30=0# and #2x^2-8y^2=-48y+90#?

##### 1 Answer

Dec 23, 2016

Illustrative fine Socratic graph is inserted.

#### Explanation:

Add and subtract.

At

at

graph{(2x^2+8y^2+8x-48y+30)(2x^2-8y^2+48y-90)=0 [-10, 10, -5, 10]}

Note that the intersecting curves are an ellipse and a hyperbola.