Question

How do you find the exact value of 2 cos pi/3 - 6 tan pi/3?

Answer 1

`1 - 6sqrt3`

Explanation:

Trig table -->
`2cos (pi/3) = 2(1/2) = 1`
`6tan (pi/3) = 6(sqrt3)`
Therefor,
`2cos (pi/3) - 6tan (pi/3) = 1 - 6sqrt3`