Question

How do you find the exact value of sin 5Pi/4?

Answer 1

`-sqrt2/2`

Explanation:

`(5pi)/4" is situated in the third quadrant hence"`

`sin((5pi)/4)<0`

`"the "color(blue)"related acute angle is"`

`(5pi)/4-pi=pi/4`

`rArrsin((5pi)/4)=-sin(pi/4)=1/sqrt2=sqrt2/2`

Answer 2

`sin((5pi)/4)=-sqrt2/2`

Explanation:

`sin((5pi)/4)=sin(pi+pi/4)=sinpicos(pi/4)+cospisin(pi/4)=0-sqrt2/2=-sqrt2/2`