How do you find the exact value of $sin((7pi)/6- pi/3)$ ?

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Answer 1 · 2016-05-04T07:30:40

$sin((7pi)/6-pi/3)=1/2$

$sin((7pi)/6-pi/3)$

= $sin((7pi)/6-(2pi)/6)$

= $sin((5pi)/6)$

= $sin(pi-pi/6)$

= $sin(pi/6)$

= $1/2$

How do you find the exact value of sin((7pi)/6- pi/3)sin((7pi)/6- pi/3)?