How do you find the exact value of #tan(π/3) times sin(π/2) + cos(π)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Shwetank Mauria Jul 1, 2016 #tan(pi/3)xxsin(pi/2)+cospi=sqrt3-1# Explanation: As #tan(pi/3)=sqrt3#, #sin(pi/2)=1# and #cospi=-1# #tan(pi/3)xxsin(pi/2)+cospi# = #sqrt3xx1+(-1)# = #sqrt3-1# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 1378 views around the world You can reuse this answer Creative Commons License