Question

How do you find the exact values of the six trigonometric function of `theta` if the terminal side of `theta` in the standard position contains the point (-15,8)?

Answer 1

In this case the terminal side of t is in Quadrant 2.
`tan t = 8/-15 = - 8/15`
`cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 64/225) = 225/289`
`cos t = - 15/17` (because t is in Quadrant 2)
`sin t = cos t.tan t = (-15/17)(-8/15) = 8/17`
`cot t = 1/(tan) = - 15/8`
`sec t = 1/(cos) = - 17/15`
`csc t = 1/(sin) = 17/8`