How do you find the focus and directrix of #-2y^2=4x#?
1 Answer
Jan 18, 2017
Its focus is
Its directrix is
Explanation:
Given -
#-2y^2=4x#
#y^2=(4x)/(-2)#
#y^2=-2x# It can be written in the form#y^2 =-4ax#
#y^2 =-1/2*4*x#
Its focus is
Its directrix is
