How do you find the following product #(8y+ 3)^2#?

1 Answer
Oct 25, 2016

Answer:

Use the FOIL method to get
#64y^2+48y+9#

Explanation:

The FOIL method is the easiest way to simplify any expressionxx which involve squaring binomials. First, I write it out like this:

#(8y+3)xx(8y+3)#

Next, use the FOIL method. Each letter represents the numbers you need to multiply
F: First numbers. #" "8yxx8y=64y^2#
O: Outside numbers. #" "8y*3=24y#
I: Inside numbers. #" "8y*3=24y#
L: Last numbers. #" " 3xx3=9#

Then, simplify. This usually involves adding the "O" and the "I" products together, resulting in the answer:

#64y^2+24y+24y+9#
#64y^2+48y+9# = answer