# How do you find the hypotenuse when the other 2 sides' measurements are 3 feet and 4 feet?

Oct 18, 2015

$h = 5$

#### Explanation:

By Pythagoras' Theorem:

(hypotenuse)$^ 2$ = (base)$^ 2$ + (perpendicular)$^ 2$
${\left(h\right)}^{2} = {\left(3\right)}^{2} + {\left(4\right)}^{2}$
${h}^{2} = 9 + 16$
${h}^{2} = 25$
$h = \sqrt{25}$
$h = 5$