How do you find the important parts of the equation to graph the function y = -x^2 + 3?
1 Answer
Jan 15, 2017
Refer the explanation section
Explanation:
Given -
y=-x^2+3
Find the vertex first-
If the quadratic equation is in the form
x=(-b)/(2a)
Since there is no
y=-x^2+0x+3
x=(-(0))/(2 xx (-1))=0
At
y=-0^2+3=3
The vertex is
Then we have to decide whether the curve is concave downwards or upwards. That is given by the second derivative.
dy/d=-2x
(d^2y)/(dx^2)=-2<0
Since the second derivative is less than zero, the curve is concave downwards.
Take two points to the right of zero [ x-coordinate of the vertex] and two points to the left of zero. Find the corresponding
Plot the pairs in a graph sheet. Join all the points.
See the Table
See the graph