How do you find the intercepts for #3x + 4y = -4#?

2 Answers
Jun 16, 2018

Answer:

#"x-intercept "=-4/3," y-intercept "=-1#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArr0+4y=-4rArry=-1larrcolor(red)"y-intercept"#

#y=0rArr3x+0=-4rArrx=-4/3larrcolor(red)"x-intercept"#
graph{(y+3/4x+1)((x-0)^2+(y+1)^2-0.04)((x+4/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Jun 16, 2018

Answer:

#x / -(4/3) + y/-1 = 1# is the intercept form of the line.

x-intercept #= (4/3)#, y-intercept #= -1#

Explanation:

Intercept form of equation is #x/a + y/b = 1#

#3x + 4y = -4#

#-(3/4)x - cancel(4/4)y = 1#

# x / -(4/3) + y/-1 =1#

x-intercept #= -(4/3)#, y-intercept #= -1#