How do you find the intercepts for #f(x) = 2x^2 - 5x -3#?

1 Answer
Jun 19, 2015

Answer:

Given your function #y=f(x)#
y-inercept: #x=0, y=-3#
x-intercept: #x_1=3, y=0#
and #x_2=-1/2, y=0#

Explanation:

First you set #x=0# into your equation and get #y=f(0)=-3#.
Second you set #y=0# and solve the quadratic equation:
#2x^2-5x-3=0# using the Quadratic Formula:
#x_(1,2)=(5+-sqrt(25+24))/4=(5+-7)/4=#
#x_1=12/4=3#
#x_2=-2/4=-1/2#