How do you find the intercepts for #y=|x-1|#?

1 Answer
Apr 7, 2017

Answer:

X-intercept: #(1,0)#
Y-intercept: #(0,1)#

Explanation:

graph{(y-|x-1|)((x-1)^2+y^2-0.02)(x^2+(y-1)^2-0.02)=0 [-10, 10, -5, 5]}

The x-intercept is the point when the graph meets the x-axis. It is when #y=0#. So, to find the x-intercept, set #y=0# and find the value of #x#: #0=|x-1|#. The only value that satisfies this equation is #x=1#. The x-intercept is #(1,0)#.

The y-intercept is the point when the graph meets the y-axis, or when #x=0#. So, set #x=0# and find the value for #y#. Thus, #y=|x-1|=|0-1|=1#. The y-intercept is #(0,1)#.

Be careful though, in some functions there can be multiple x-intercepts and y-intercepts.