Question

How do you find the intercepts for `y=|x-1|`?

Answer 1

X-intercept: `(1,0)`
Y-intercept: `(0,1)`

Explanation:

graph{(y-|x-1|)((x-1)^2+y^2-0.02)(x^2+(y-1)^2-0.02)=0 [-10, 10, -5, 5]}

The x-intercept is the point when the graph meets the x-axis. It is when `y=0`. So, to find the x-intercept, set `y=0` and find the value of `x`: `0=|x-1|`. The only value that satisfies this equation is `x=1`. The x-intercept is `(1,0)`.

The y-intercept is the point when the graph meets the y-axis, or when `x=0`. So, set `x=0` and find the value for `y`. Thus, `y=|x-1|=|0-1|=1`. The y-intercept is `(0,1)`.

Be careful though, in some functions there can be multiple x-intercepts and y-intercepts.