How do you find the inverse of $arctan (x + 3)$ $arctan(x+3)$ and is it a function?

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Answer 1 · 2017-02-27T10:09:42

Inverse of $arctan (x + 3)$ $arctan(x+3)$ is $tan x - 3$ $tanx-3$

Let $y = arctan (x + 3)$ $y=arctan(x+3)$ then $tan y = x + 3$ $tany=x+3$ and $x = tan y - 3$ $x=tany-3$

Hence, inverse of $arctan (x + 3)$ $arctan(x+3)$ is $tan x - 3$ $tanx-3$

How do you find the inverse of arctan(x+3)arctan(x+3)arctan(x+3) and is it a function?