Question

How do you find the inverse of `f(x) = log 2^x`?

Answer 1

`f^-1x=x/log2`

Explanation:

If a given equation is `f(x)=y` then the inverse of that function is `f^-1(y)=x`

Now, given `f(x)=log2^x\impliesy=log2^x`

I'm sure you know this general log formula `log_nm^l=llog_nm`
So applying this the the equation above, `y=xlog2`

So that means `y/log2=x` and fora fact, we know that `f^-1(y)=x`, so `f^-1y=y/log2`

Just replace `y` with `x` to get the general formula