How do you find the inverse of #f(x) = log 2^x#?

1 Answer
Jan 26, 2016

#f^-1x=x/log2#

Explanation:

If a given equation is #f(x)=y# then the inverse of that function is #f^-1(y)=x#

Now, given #f(x)=log2^x\impliesy=log2^x#

I'm sure you know this general log formula #log_nm^l=llog_nm#
So applying this the the equation above, #y=xlog2#

So that means #y/log2=x# and fora fact, we know that #f^-1(y)=x#, so #f^-1y=y/log2#

Just replace #y# with #x# to get the general formula