How do you find the inverse of $f(x)=(x+2)/(x-1)$ and is it a function?

Question

3153 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-07T13:42:03

$f^-1(x)=(x+2)/(x-1)$

$f(x)=(x+2)/(x-1)$

$y=(x+2)/(x-1)$

$y*x-y=x+2$

$y*x-x=y+2$

$x(y-1)=(y+2)$

$x=(y+2)/(y-1)$

$"change x and y vice versa"$

$y=(x+2)/(x-1)$

$f^-1(x)=(x+2)/(x-1)$

$"or simply:"$

$f(x)=(a x+b)/(c x+d)$

$f^-1 (x)=(-d x+b)/(c x+a)$

How do you find the inverse of f(x)=(x+2)/(x-1)f(x)=(x+2)/(x-1) and is it a function?