# How do you find the inverse of y=ln(x+1)?

Jul 9, 2016

The inverse is found algebraically by switching the x and y values.

#### Explanation:

$y = \ln \left(x + 1\right)$

$x = \ln \left(y + 1\right)$

${e}^{x} = y + 1$

$y = {e}^{x} - 1$

Practice exercises:

1. Determine the inverse:

$y = {2}^{x - 5}$

$y = {\left(x - 2\right)}^{3} + 6$

$y = \sqrt[4]{{x}^{2} + 7} - 1$

Hopefully this helps, and good luck!