How do you find the inverse of y = -log_4x?

1 Answer
Feb 2, 2016

f^-1(x)=4^-x

Explanation:

Given that y=-log_4x. It can also be written as f(x)=-log_4x
This means that f(x)=y\impliesf^-1(y)=x

Now, I believe you're accustomed to the realm of logarithms so that you know y=-log_4x\implies-y=log_4x\implies4^-y=x
We've written above that f^-1(y)=x so that just means f^-1(y)=4^-y.
Replacing the y parameter by the x parameter is just what you'll find to be the answer.