Question

How do you find the inverse of `y=-log_5(-x)`?

Answer 1

`x=-5^(-y)`

Explanation:

`y=-log_5(-x)`, with x<0

`-y=log_5(-x)`, with x<0

if we have `a =log_b(c)` we will have `b^a=c`, if c>0

`5^(-y)=-x`

`x=-5^(-y)= -1/(5^y)<0 AA y in RR`