How do you find the inverse of $y=log(x-3)$ ?

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Answer 1 · 2016-08-12T21:23:28

Switch around the x and y values:

$y = log(x - 3)$

$x = log(y - 3)$

$10^x = y - 3$

$y = 10^x + 3$

$f^-1(x) = 10^x + 3$

Hopefully this helps!

How do you find the inverse of y=log(x-3)y=log(x-3)?