# How do you find the length of the diagonal of the rectangle when the length is 6 meters and the width is 4 meters?

$d \cong 7.2111 m$
${d}^{2} = {6}^{2} + {4}^{2}$
${d}^{2} = 52$
$d = \sqrt{52} \cong 7.2111 m$