How do you find the magnitude and direction for U: magnitude 140, bearing 160° V: magnitude 200, bearing 290°?

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Answer 1 · 2016-07-03T05:29:19

#U=(-140 cos 20^o, 140 sin 20^o) = (-131.56, 47.883)# and
#V = (-200 cos 10^o, -200 sin 10^o) = (-196.96, -34.730)#.

If m is the magnitude and b is the bearing (with respect to x-axis),

the vector is #( m cos b, m sin b)#.

Here, #U = (140 cos 160^o, 140 sin 160^o)#

#=(-140 cos 20^o, 140 sin 20^o)#

# = (-131.56, 47.883)# and

#V =(299 cos 190^o, 200 sin 190^o)#

#= (-200 cos 10^o, -200 sin 10^o)#

# = (-196.96, -34.730)#.