# How do you find the magnitude of MP given M(2,-1) and P(-3,4)?

Jul 31, 2016

$5 \sqrt{2}$.

#### Explanation:

$\vec{M P}$=position vector of P-position vector of M

$= \left(- 3 , 4\right) - \left(2 , - 1\right)$

$= \left(- 3 - 2 , 4 - \left(- 1\right)\right)$

$= \left(- 5 , 5\right)$

Hence, the magnitude of $\vec{M P} = | | \vec{M P} | |$

$= \sqrt{{\left(- 5\right)}^{2} + {5}^{2}} = \sqrt{25 + 25} = \sqrt{50} = 5 \sqrt{2}$.