Question

How do you find the max or minimum of `f(x)=-x^2-9`?

Answer 1

max at`" "(0,-9)`

Explanation:

`f(x)=-x^2-9`

there is no `x` term so it is straightforward to identify max/min.

because the function has `-x^2`, it means `f(x)` will have a maximum value and not a minimum value.

This will occur when the `x^2` term is `0`.

`f_max(x)=0-9=-9`

so max at`" "(0,-9)` as can be seen by the graph

graph{-x^2-9 [-40, 40, -20, 20]}