# How do you find the maximum or minimum of #f(x)=3x^2#?

##### 1 Answer

Nov 14, 2016

The function has a minimum at

#### Explanation:

Given -

#y=3x^2#

#dy/dx=6x#

#(d^2y)/(dx^2)=6#

#dy/dx=0 => 6x=0#

#x=0/6=0#

At

At

Hence the function has a minimum at