Question

How do you find the maximum or minimum of `f(x)=3x^2`?

Answer 1

The function has a minimum at `x=0`

Explanation:

Given -

`y=3x^2`

`dy/dx=6x`

`(d^2y)/(dx^2)=6`

`dy/dx=0 => 6x=0`

`x=0/6=0`

At `x=0 ; (d^2y)/(dx^2)=6>0`

At `x=0; dy/dx=0; (d^2y)/(dx^2)>0`

Hence the function has a minimum at `x=0`