# How do you find the midpoint of the line segment joining A(-1,3) and B(-5,9)?

Jul 27, 2016

$\left(- 3 , 6\right)$

#### Explanation:

It is the mean values

$\implies {P}_{\text{mid}} \to \left(x , y\right) = \left(\frac{- 1 - 5}{2} , \frac{3 + 9}{2}\right) = \left(- 3 , 6\right)$

Jul 27, 2016

$\left(- 3 , 6\right)$.

#### Explanation:

The midpoint $M \left(x , y\right)$ of the segment joining pts. $\left({x}_{1} , {y}_{1}\right) \mathmr{and} \left({x}_{2} , {y}_{2}\right)$ is given by $x = \frac{{x}_{1} + {x}_{2}}{2} , y = \frac{{y}_{1} + {y}_{2}}{2}$.

Hence, the reqd. mid-pt. is $\left(- 3 , 6\right)$.

Jul 27, 2016

$M \left(- 3 , 6\right)$

#### Explanation:

In easy English this is:

"Average of the x-values and the average of the y-values."

The formula is M((x_1 + x_2)/2; (y_1+ y_2)/2)

M((-1-5)/2; (3+9)/2)

M((-6)/2; 12/2)

=$M \left(- 3 , 6\right)$